Rational Numbers
The set formed by fractions that are equivalent to a given fraction represents a single number. Such a number is called a rational number. We can represent a rational number using any element of the set that defines this number.
Where a and b are coprime numbers, let the set
$$A=\left\{\frac{a}{b}, \frac{2a}{2b}, \frac{3a}{3b}, \cdots, \frac{ka}{kb}, \cdots \right\}\,\, k \in \mathbb{Z} $$
*(Note: Adjusted the textbook typo inside the set from $\frac{a}{2b}$ to the standard equivalent fraction $\frac{a}{b}$).*
be given. Since the fractions that are elements of this set are equivalent, set A represents a rational number. The representative element
of this set is \( \frac{a}{b} \). Just as the rational number represented by set A can be denoted by \( \frac{a}{b} \), it can also be denoted by any other element of this set.
Warning:
Every fraction represents a rational number. Each of the numbers $$-\frac{2}{7}, -\frac{4}{3}, \frac{9}{7}, \frac{11}{12} , 0, 8, \cdots $$ represents a rational number.
ORDERING RATIONAL NUMBERS
Rational numbers can be compared in terms of magnitude in 5 different ways:
- For two positive rational numbers with equal denominators, the one with the smaller numerator is smaller.
$$ \frac{3}{7} < \frac{4}{7} < \frac{5}{7} $$
Example:
$$ \left\{ \frac{3}{4}, \frac{5}{8}, \frac{4}{6} \right\} $$
Let’s order these numbers from smallest to largest.
If we equalize the denominators of the fractions at their least common multiple; $\text{LCM}(4, 8, 6) = 24$. From here:
\[\begin{array}{l l l}
\displaystyle\frac{3}{4}\cdot \displaystyle\frac{6}{6} =\displaystyle\frac{18}{24} \\
\displaystyle\frac{5}{8} \cdot \displaystyle\frac{3}{3} = \displaystyle\frac{15}{24} \\
\displaystyle\frac{4}{6} \cdot \displaystyle\frac{4}{4} =\displaystyle\frac{16}{24} \quad \text{then} \\
\displaystyle\frac{15}{24} <\frac{16}{24} <\frac{18}{24} \quad \text{Therefore} \\
\displaystyle\frac{5}{8} <\displaystyle\frac{4}{6} <\displaystyle\frac{3}{4} \quad \text{is ordered this way.}
\end{array}\]
2. For two positive rational numbers with equal numerators, the one with the smaller denominator is larger.
$$ \frac{8}{3} > \frac{8}{5} > \frac{8}{6} $$
Example:
$$ \left\{ \frac{3}{5}, \frac{2}{6}, \frac{4}{7} \right\} $$
Let’s order these numbers.
If we equalize the numerators of the fractions at their least common multiple; $\text{LCM}(3, 2, 4) = 12$. From here:
\[\begin{array}{l l } {\displaystyle\frac{3}{5} \cdot \displaystyle\frac{4}{4} = \displaystyle\frac{12}{20}} \end{array}\]
\[\begin{array}{l l } {\displaystyle\frac{2}{6} \cdot \displaystyle\frac{6}{6} = \displaystyle\frac{12}{36}} \end{array}\]
\[\begin{array}{l l } {\displaystyle\frac{4}{7} \cdot \displaystyle\frac{3}{3} = \displaystyle\frac{12}{21}} \end{array}\]
then
$${\frac{12}{20} >\frac{12}{21} > \frac{12}{36} \Rightarrow \frac{3}{5}> \frac{4}{7} >\frac{2}{6} }$$ is ordered this way.
Where \(\displaystyle{\frac{a}{b} } \quad \) and \( \quad \displaystyle{\frac{c}{d} } \) are two positive fractions,
\[\begin{array}{l l } \text{if } {\displaystyle\frac{a}{b} \div \displaystyle\frac{c}{d}} > 1 \quad \text{then} \quad {\displaystyle\frac{a}{b} >\displaystyle\frac{c}{d} } \end{array}\]
\[\begin{array}{l l } \text{if } {\displaystyle\frac{a}{b} \div \displaystyle\frac{c}{d}} < 1 \quad \text{then} \quad {\displaystyle\frac{a}{b} <\displaystyle\frac{c}{d} } \end{array}\]
\[\begin{array}{l l } \text{if } {\displaystyle\frac{a}{b} \div \displaystyle\frac{c}{d}} = 1 \quad \text{then} \quad {\displaystyle\frac{a}{b} =\displaystyle\frac{c}{d} } \quad \text{holds.} \end{array}\]
*(Note: Corrected a subtle textbook typo where the text repeated a less-than sign instead of an equality check inside the final condition).*
Example:
Let’s examine the fractions \( \displaystyle{\frac{2}{3} } \quad \) and \( \quad \displaystyle{\frac{3}{4} } \).
\[\begin{array}{l l } {\displaystyle\frac{2}{3} \div \displaystyle\frac{3}{4} =\displaystyle\frac{2}{3} \cdot \displaystyle\frac{4}{3} =\displaystyle \frac{8}{9} < 1} \end{array}\]
Since the result is less than 1, the dividend fraction \(\displaystyle {\frac{2}{3} } \quad \) is smaller. That is, \(\displaystyle{\frac{2}{3} < \frac{3}{4} } \).
4. Rational numbers can be compared by converting them into decimal numbers. For any two decimal numbers, the one with the larger integer part is larger. Decimal numbers with equal integer parts are compared by looking at their fractional parts after the decimal point.
Namely: From left to right, digits in the same place value are examined sequentially. The first differing digits encountered in corresponding place values from left to right are compared. The decimal number containing the larger digit in this place value is the larger number.
Examples:
- 3.21 > 2.95 (integer parts are different and 3 > 2)
- Let’s compare the numbers 2.3428 and 2.3432. Since their integer parts are identical, comparing their decimal digits sequentially from left to right shows that the first place value where they differ is the thousandths place. Since 2 < 3 for these digits, the number with 2 in its thousandths place is smaller.
- Let’s compare the numbers 3.418, 3.602, and 3.42. If we order these numbers as in the example above, it results in 3.602 > 3.42 > 3.418.
5. For positive fractions where the difference between the numerator and the denominator is equal, as the numbers in the numerator and denominator grow larger; the value of proper fractions increases, while the value of improper fractions decreases.
\[\begin{array}{l l }
{\displaystyle\frac{3}{8} <\displaystyle\frac{4}{9} <\displaystyle\frac{7}{12}< \displaystyle\frac{8}{13} \cdots} \\ {\displaystyle\frac{5}{3} >\displaystyle\frac{7}{5} >\displaystyle\frac{9}{7} >\displaystyle\frac{10}{8} \cdots }\\
\end{array}\]
Warning: When comparing negative numbers, they are first ordered without considering their signs. Finally, all numbers are multiplied by -1, which reverses the direction of the inequality.
Example:
\[\begin{array}{l l } a= {-\displaystyle\frac{11}{10}} , b= {-\displaystyle\frac{101}{100}} , c= {-\displaystyle\frac{1001}{1000}} \end{array}\]
Accordingly, let’s determine the relationship between the numbers a, b, and c.
If we sort the given numbers without taking their negative signs into account:
\[ {\frac{11}{10}} > {\frac{101}{100}} > {\frac{1001}{1000}} \]
If we multiply every side of the inequality by -1:
\[ {-\frac{11}{10}} < {-\frac{101}{100}} < {-\frac{1001}{1000}} \]
Accordingly, we get a < b < c.
Example:
Let’s find the set of digits that can replace X in the inequality 24.48 < 24.X5.
If we compare the tenths place value; for the given inequality to hold true, the digits that can replace X must be greater than or equal to 4. Since the hundredths place of the right-hand value is 5, which is smaller than 8, X cannot be exactly 4 because 24.48 is not less than 24.45. Therefore, X must be strictly greater than 4. The set of digits that can be written in place of X is:
$$\{5,6,7,8,9\}$$
is found.